de_sert » 02 июл 2013, 12:38
0.6 x Q x F/E = D
Q is the available drive flow in gallons per minute, F is the fall in feet from the water source to the ram, E is the elevation from the ram to the water outlet, and D is the flow rate of the delivery water in gallons per minute. 0.6 is an efficiency factor and will differ somewhat between various ram pumps. For instance, if 12 gallons per minute is available to operate a ram pump, then pump is placed 6 feet below the water source, and the water will be pumped up an elevation of 20 feet, the amount of water that may be pumped with an appropriately-sized ram pump is
0.6 x 12 gpm x 6 ft / 20 ft = 2.16 gpm
изменим в формуле 20 футов на 7.8 (т.е. 1,3 от 6 футов) и получим 5,53 галона в минуту, т.е. почти 50%